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18 June, 05:22

Find the area of the triangle if 8 and 12 are a leg and hypotenuse.

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  1. 18 June, 05:35
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    This is a right triangle; In a right triangle the base and the height are the legs.

    We have to calculate the other leg.

    Pythagoras Theroem:

    leg₁²+leg₂²=hypotenuse²

    dа ta:

    leg₁=8

    hypotenuse=12

    Therefore:

    8²+leg₂²=12²

    64+leg₂²=144

    leg₂²=144-64

    leg₂²=80

    leg₂=√80=4√5

    Area of a triangle = (base * height) / 2 = (leg₁*leg₂) / 2 = (8) (4√5) / 2=16√5

    Answer: the area of this triangle would be 16√5 u²
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