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20 October, 16:44

David is standing 5000 feet away from the base of a cell phone tower. The angel of elevation from his eyes to the top of the tower is 78 degrees. If David's eyes are 6 feet above the ground how y'all is the tower?

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  1. 20 October, 17:05
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    To solve this proble you must apply the proccedure shown below:

    1. You have that:

    - David is standing 5000 feet away from the base of a cell phone tower. and the angel of elevation from his eyes to the top of the tower is 78 degrees.

    - David’s eyes are 6 feet.

    2. Therefore, you have:

    Tan α=opposite/adjacent

    Tanα=x/5000

    x = (5000) (Tan (78°))

    x=23,523.15 feet

    3. Then, you have that the height of the tower is:

    h=6 feet+23,523.15 feet

    h=23,529.15 feet

    The answer is:23,529.15 feet
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