How do i simplify: (sin pi/2 - x) / (cos pi/2 - x)

and

sec^2x-1 / secx-1

Question

Zachery Villegas

Mathematics

3 June, 04:36

How do i simplify: (sin pi/2 - x) / (cos pi/2 - x)

and

sec^2x-1 / secx-1

+1

Answers (1)

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Curly · Answer 1

tan (x) = sin (x) / cos (x)

When x = pi/2-x, it's the same thing but you just substitute

sin (pi/2-x) / cos (pi/2-x) = tan (pi/2-x)

1/cos (x) = secx

sec^2 (x-1) / sec (x-1) = sec (x-1) = 1/cos (x-1)

How do i simplify: (sin pi/2 - x) / (cos pi/2 - x)andsec^2x-1 / secx-1

How do i simplify: (sin pi/2 - x) / (cos pi/2 - x)

and

sec^2x-1 / secx-1