If the area of a rectangle 16s2t and the length is 8st2, what would the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

Area = Length x Width

Substituting the given values:

16S^2 t = 8St^2 x Width

Manipulating for Width:

Width = 16S^2 t / 8St^2

Rewriting the squared terms in simplified form:

Width = 16 x S x S x t / 8 x S x t x t

Cancelling the like terms

Width = 16 x S / 8 x t

Cancelling the numeric terms:

Width = 2S / t