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Mathematics
9 September, 08:47
Find the derivative of the function.
y=x^2lnx^2
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Izabella Garrett
9 September, 09:07
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Correct answer: y = 2x (㏑x² + 1)
Step-by-step explanation:
We will use the product rule for this derivation
Let be x² = U and ㏑x² = V
Product rule is:
dy = dU · V + U · dV
y = 2x · ㏑x² + x² · 1/x² · 2x = 2x · ㏑x² + 2x = 2x (㏑x² + 1)
y = 2x (㏑x² + 1)
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