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Which is a polar form of the following parametric equations?

x=4sin^2 theta

Y=4 sin theta cos theta

a) r=1/4sin theta cod theta

b) r=2

c) r=16sin^2 theta

d) r=4sin theta

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Answers (1)
  1. 23 May, 06:38
    0
    r=4sin (theta)

    Step-by-step explanation:

    x=4sin^2 (theta) y=4sin (theta) cos (theta

    theta=arcsin ((sqrtx) / 2)

    y=4sin (arcsin (sqrtx/2)) cos (arcsin (sqrtx/2))

    graph each to see they line up
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