A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 16 square feet, find the lengths of the sides of the poster and sign

Question

Landen Farmer

Mathematics

19 May, 03:05

A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 16 square feet, find the lengths of the sides of the poster and sign

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Answers (1)

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Emilio Ellison · Answer 1

(x-2) (x-2) = Area of square poster

(x) (x) = Area of square sign

A=Area of square sign

B=Area of square poster

A-B=16

x^2 - (x-2) (x-2) = 16

x^2 - (x^2-4x+4) = 16

x^2-x^2+4x-4x=16

0=16

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