Is 4 times as old as his. together their ages are 35. how old is jamie?

We assume that jamie is a boy or whatever

his sibbling is sibbling x

together, ages are 35

either jamie is 4 times sibbling x or sibbling x is 4 times jamie

anyway

lets say jamie=y and sibbling x=x

if we solve for jamie is 4 times as old as x then we can switch them if we are wrong

jamie is 4 times sibbling x age

x=4y

together it is 35

x+y=35

sub 4y for x

4y+y=35

5y=35

divide both sides by 5

y=7

sub back

x=4y

x=4 (7)

x=28

either it is

jamie is 28 and sibbling is 7 or

sibbling is 28 and jamie is 7

depends but you didn't say who is older and who is 4 times of who