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31 March, 15:31

The graph below shows the function f (x) = StartFraction 5 x + 10 Over x squared + 7 x + 10 EndFraction.

On a coordinate plane, a hyperbola is shown. Both curves approach x = negative 5. There is a hole at x = negative 2.

Where is the removable discontinuity of f (x) located?

x = - 5

x = 0

x = - 2

x = 5

+3
Answers (2)
  1. 31 March, 15:43
    0
    I believe it would be - 5 but, I might be wrong.
  2. 31 March, 15:54
    0
    x=-2

    Step-by-step explanation:

    got it right on edge. brainliest?
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