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20 April, 23:17

What is the surface area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a length of 48 in? A. 529.86 in2 B. 256.22 in2 C. 950.02 in2 D. 849.73 in2

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  1. 20 April, 23:21
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    The surface area of the cylindrical ring is given by

    πdh

    where d is the diameter and h is the height:

    π•6.3•48 = 950.02

    The answer is C. 950.02 in^2
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