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25 December, 21:33

If f (x) = x1/2-x and g (x) = 2x^3-x1/2-x, find f (x) - g (x)

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  1. 25 December, 21:46
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    F (x) = x/2-x and g (x) = 2x^3-x/2-x so

    f (x) - g (x) = x/2-x-2x^3+x/2+x

    f (x) - g (x) = - 2x^3+2x/2

    f (x) - g (x) = - 2x^3+x or if you prefer:

    f (x) - g (x) = x (-2x^2+1)
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