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10 December, 09:56

F (x) = 2x^2-2x+3 solve using the quadratic formula

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  1. 10 December, 10:19
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    x = [-b + -sq root (b^2 - 4ac) ] / 2a a=2 b=-2 c=3

    x = [--2 + - sq root (4 - 4*2*3) ] / 2*2

    x = [2 + - sq root (-20) ] / 4] / 4

    x1 = 2 + 4.472135955 i / 4

    x1 =.5 + 1.1180339887i

    x2 = 2 - 4.472135955 i / 4

    x2 =.5 - 1.1180339887i
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