If the diagonal path is 750 feet long and the width of the park is 450 feet, what is the length, in feet, of the park?

A. 675 ft.

B. 550 ft.

C. 600 ft.

D. 650 ft.

C, 600 ft.

Step-by-step explanation:

a^2+b^2=c^2

C is always the hypotenuse/diagonal. Let A represent length and B represent width.

A^2+450^2=750^2

A^2+202500=562500

562500-202500=360000=A^2

take the square root of both sides to solve for A and the value of A is 600.

600 feet

Step-by-step explanation:

I am assuming that the park is rectangular, and the together, the length, with and diagonal form a right triangle.

In this case, we are given

Diagonal = 750 ft = hypotenuse

Width = 450 feet

Find length L

Using the Pythagorean theorem,

L² + 450² = 750²

L² = 750² - 450² = 360,000

L = √360,000 = 600 feet