Solve the problem by setting up and solving a system of three linear equations in three variables. a box contains $7.20 n nickels, dimes, and quarters. there are 42 coins in all, and the sum of the numbers of nickels and dimes is 2 less than the number of quarters. how many coins of each kind are there

Question

Justice Nichols

Mathematics

26 October, 08:12

Solve the problem by setting up and solving a system of three linear equations in three variables. a box contains $7.20 n nickels, dimes, and quarters. there are 42 coins in all, and the sum of the numbers of nickels and dimes is 2 less than the number of quarters. how many coins of each kind are there

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Answers (1)

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Janessa Shepard · Answer 1

N+d+q=42

n+d=q-2

q-2+q=42

2q=44

q=22

n+d=20

5n+10d+25q=720

n+2d+5q=144

n+2d+110=144

n+2d=34

n=-d+20

-d+20+2d=34

d=14

n=6

There are 22 quarters, 14 dimes, and 6 nickles.