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Ethen Nolan
Mathematics
22 April, 13:35
Evaluate the series 6+2+2/3+2/9 + ... a6
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Ayaan Rosales
22 April, 13:50
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The given above is a series that is geometric with the value of common ratio equal to 1/3. The sum of the first six terms of the sequence is,
S6 = a1 x (1 - r^6) / (1 - r)
Substituting the given,
S6 = 6 x (1 - (1/3) ^6) / (1 - 1/3)
The final value of the series is 728/81.
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