What is the 9th term of the geometric sequence 5 - 25 125

Step-by-step explanation:

hello:

the n-ieme term is : An=A1*r^ (n-1)

A1 the first term r : the common ratio

in this exercice : A1 = 5 r = 125/-25=-25/5 = - 5 n = 9

A9=5 * (-5) ^ (9-1) = 5*5^8 = 5^9 because : ((-5) ^ (8) = 5^8)