A standard pair of six-sided dice is rolled. What is the probability of rolling a sum less than or equal to 44? Express your answer as a fraction or a decimal number rounded to four decimal places.

Question

A standard pair of six-sided dice is rolled. What is the probability of rolling a sum less than or equal to 44?

Since the highest score that we can get by rolling a pair of six-sided dice is 6+6 = 12 so there is no chance of getting a score of 44. It must be a typing error the correct digit must be 4.

Answer:

P (sum ≤ 4) = 1/6 = 0.1667

Step-by-step explanation:

Since each dice can have 6 possible outcomes

The total possible outcomes of 2 dice are = 6*6 = 36

Let us list all the possible combinations that we can get by rolling 2 six-sided dice.

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we are interested in only those outcomes whose sum is less or equal to 4.

(1,1) (1,2) (1,3) (2,1) (2,2) (3,1)

So there are 6 such outcomes where sum ≤ 4

So the probability of

P (sum ≤ 4) = 6/36

P (sum ≤ 4) = 1/6

P (sum ≤ 4) = 0.1667