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25 October, 15:38

A ball is thrown into the air with a initial velocity of 25 meters per second. The function h (t) + -4.9t^2+25t+6 represents the height of the t in seconds. ball above the ground in meters, with respect to time. at h (3) then the height of the ball would be

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  1. 25 October, 16:08
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    36.9 m

    Step-by-step explanation:

    h (t) = - 4.9t² + 25t + 6

    At t = 3:

    h (3) = - 4.9 (3) ² + 25 (3) + 6

    h (3) = - 44.1 + 75 + 6

    h (3) = 36.9

    After 3 seconds, the ball will have a height of 36.9 meters.
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