In a certain Algebra 2 class of 29 students, 14 of them play basketball and 8 of them play baseball. There are 9 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

2/29

Step-by-step explanation:

If 9 play none, of the 29 students, 29-9 = 20 play at least one. If 14 play basketball, then 20-14 = 6 play only baseball. Since 8 play baseball, there must be 8-6 = 2 who play both baseball and basketball.

Choosing at random, the probability is 2/29 that a student will be chosen who plays both sports.