A minister claims that more than 60% of the adult population attends a religious service at least once a month. The null and alternative hypotheses you'd use to test this claim would be:

a. H0 : μ =.6, Ha: μ >.6

b. H0 : p =.6, Ha: p >.6

c. H0 : p =.6, Ha: p ≠.6

d. H0 : pˆ =.6, Ha: pˆ >.6

e. H0 : x =.6, Ha: x >.6

Question

Dana Henson

Mathematics

8 May, 15:59

A minister claims that more than 60% of the adult population attends a religious service at least once a month. The null and alternative hypotheses you'd use to test this claim would be:

a. H0 : μ =.6, Ha: μ >.6

b. H0 : p =.6, Ha: p >.6

c. H0 : p =.6, Ha: p ≠.6

d. H0 : pˆ =.6, Ha: pˆ >.6

e. H0 : x =.6, Ha: x >.6

+2

Answers (1)

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Darian · Answer 1

d. H0 : pˆ =.6, Ha: pˆ >.6

Step-by-step explanation:

Given that a minister claims that more than 60% of the adult population attends a religious service at least once a month.

Here the subject of interest about a proportion of adult population who attends a religious service at least once a month.

The claim is this proportion is greater than 60% and we want to check whether this claim is true.

Hence hypotheses would be for proportion only and not mean.

Since population proportion is to be checked we use p hat

Correct answer is

d. H0 : pˆ =.6, Ha: pˆ >.6