What value of n makes the equation true? (2x^9 y^n) (4x^2 y^10) = 8x^11 y^20

n = 10

Step-by-step explanation:

(2x⁹ yⁿ) (4x² y¹⁰) = 8x¹¹ y²⁰

2*4*x⁹*x² * yⁿ * y¹⁰ = 8x¹¹ y²⁰

8x⁹⁺² * yⁿ⁺¹⁰ = 8x¹¹y²⁰

8x¹¹yⁿ⁺¹⁰ = 8x¹¹y²⁰

Now, compare the powers of y

n + 10 = 20

n = 20 - 10

n = 10