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14 November, 13:32

What value of n makes the equation true? (2x^9 y^n) (4x^2 y^10) = 8x^11 y^20

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  1. 14 November, 13:37
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    n = 10

    Step-by-step explanation:

    (2x⁹ yⁿ) (4x² y¹⁰) = 8x¹¹ y²⁰

    2*4*x⁹*x² * yⁿ * y¹⁰ = 8x¹¹ y²⁰

    8x⁹⁺² * yⁿ⁺¹⁰ = 8x¹¹y²⁰

    8x¹¹yⁿ⁺¹⁰ = 8x¹¹y²⁰

    Now, compare the powers of y

    n + 10 = 20

    n = 20 - 10

    n = 10
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