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18 May, 04:41

What value of t makes the statement true? (4x3 + 5) (2x3 + 3) = 8x6 + tx3 + 15

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  1. 18 May, 04:52
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    Know that

    if ax²+bx+c=Zx²+Rx+D then we can ssume that a=Z, b=R, and c=D

    expand

    (4x³+5) (2x³+3) = 8x⁶+22x³+15

    8x⁶+22x³+15=8x⁶+tx³+15

    8=8

    22=t

    15=15

    t=15
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