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4 September, 04:23

If the H. C. F of 210 and 55 is expressible in the form of 210*5 + 55y, find 'y'?

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  1. 4 September, 04:28
    0
    y = - 19

    Step-by-step explanation:

    Express 210 and 55 as products of their prime factors, that is

    210 = 2 * 3 * 5 * 7

    55 = 5 * 11

    Identify the prime factors that both numbers have in common and multiply them.

    Here only 5 is common, thus

    HCF = 5

    Thus

    5 = 210 * 5 + 55y, that is

    5 = 1050 + 55y (subtract 1050 from both sides)

    - 1045 = 55y (divide both sides by 55)

    y = - 19
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