Have an average weight of 16 ounces and a standard deviation of 0.2 ounces. the weights of the sugar bags are normally distributed. what is the probability that 16 randomly selected packages will have a weight in excess of 16.075 ounces?

Standardised z score = (16.075 - 16) / 0.2 = 0.375

which gives a probability of 0.1462 for selecting a package of weight 16.075

the probability of weight being excess of 16.075 = 0.5 - 0.1462 = 03538

Probability of picking 16 in excess of 16-075 = 0.3538^16 = 6.0273 * 10^-8