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6 September, 15:33

What's the fifth term of a sequence whose first term is 5 and whose common ratio is 3?

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  1. 6 September, 15:59
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    405.

    Step-by-step explanation:

    This is a geometric sequence where the nth term = a1 r^ (n - 1).

    Here a1 = 5 and r = 3 so

    the fifth term a5 = 5 (3) ^ (5-1)

    = 5 * 81

    = 405.
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