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Jan Gaines
Mathematics
5 March, 22:17
What is the discrimination of 3x^2+6x=2
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Stella Bradshaw
5 March, 22:33
0
60
D>0, there are 2 distinct real roots
Explanation:
3x2+6x-2=0
a=3, b=6, c=-2
The formula for discriminant is b2-4acSubstitute the given values.
b2-4ac
(6) 2-4 (3) (-2)
=60
therefore, D>0, there are 2 distinct real roots
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Israel Robles
5 March, 22:38
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Discriminant, not discrimination. I'm not discriminating against you.; )
You must re-write 3x^2+6x=2 in standard form: 3x^2 + 6x - 2
Here a=3, b=6 and c = - 2
The discriminant is b^2 - 4ac. Here, it's 6^2 - 4 (3) (-2), or 36 + 24, or 60.
This quadratic has two real, unequal, zeros.
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