What is the maximum or minimum of the quadratic function y = 16x^2 + 40x + 25

Question

Fury

Mathematics

2 October, 12:45

What is the maximum or minimum of the quadratic function y = 16x^2 + 40x + 25

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Azul Nelson · Answer 1

Y = 16x^2 + 40x + 25

The sign before the 16 is positive, so it's a parabola with a minimum. The x coordinate of the minimum is:

x=-b/2a=-40/32=5/4=-1.25

If you fill that in, you get y=0

so the coordinates are (1.25, 0)