Elizabeth brought a box of donuts to share. There are two-dozen (24) donuts in the box, all identical in size, shape, and color. Three are jelly-filled, four are lemon-filled, and seventeen are custard-filled. You randomly select one donut, eat it, and select another donut.

Find the probability of selecting a lemon -filled donut followed by a custard-filled donut.

P = 68/552 = 0.123 or 12.3%

Step-by-step explanation:

First, let's calculate the probability of getting a lemon donut. We have only 4 lemon donut among 24 donuts, so probability is:

P (A) = 4/24

Next, as we already ate the lemon donut, we only have 23 donuts now, and among these 23, 17 are custard filled, so probability of choosing one of those is:

P (B) = 17/23

But we want to know the probability that the custard filled donut is choosen after you eat the lemon one so:

P (B|A) = P (A) * P (B)

Replacing:

P (B|A) = 4/24 * 17/23

P (B|A) = 68/552 = 0.123 or 12.3%