Given that the rate constant for the decomposition of hypothetical compound X from part A is 1.60 M-1⋅min-1, calculate the concentration of X after 13.0min.

(min) [X] (M)

0 0.467

1 0.267

2 0.187

3 0.144

4 0.117

5 0.099

6 0.085

7 0.075

Question

Asa Rivas

Mathematics

2 December, 17:25

Given that the rate constant for the decomposition of hypothetical compound X from part A is 1.60 M-1⋅min-1, calculate the concentration of X after 13.0min.

(min) [X] (M)

0 0.467

1 0.267

2 0.187

3 0.144

4 0.117

5 0.099

6 0.085

7 0.075

+5

Answers (1)

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August · Answer 1

Using the 2nd order integrated rate law.

1/A1 = 1/A0 + Kt

A1 = 0.267

A0 = 0.467

k = 1.6

t = time

1/A13 = 1/0.467 + 1.6 (13)

1/A13 = 1/0.467 + 20.8

1/A13 = 2.141 + 20.8

1/A13 = 22.941

1 = 22.941 * A13

1/22.941 = A13

A13 = 0.04359

The concentration of X after 13 minutes is 0.04359

Given that the rate constant for the decomposition of hypothetical compound X from part A is 1.60 M-1⋅min-1, calculate the concentration of X after 13.0min.(min) [X] (M)0 0.4671 0.2672 0.1873 0.1444 0.1175 0.0996 0.0857 0.075

Given that the rate constant for the decomposition of hypothetical compound X from part A is 1.60 M-1⋅min-1, calculate the concentration of X after 13.0min.

(min) [X] (M)

0 0.467

1 0.267

2 0.187

3 0.144

4 0.117

5 0.099

6 0.085

7 0.075