If 3b+2-6b=32+5b-2b, find b

b=-5

Step-by-step explanation:

3b+2-6b=32+5b-2b (first you should collect like terms on each side.) so

3b-6b+2=32+5b-2b (lessen thing by both sides.)

-3b+2=32+3b (then you collect terms to one side)

-3b-3b=32-2

-6b=30 (you divide both sides by 6)

-b=5 (since b cannot be a negative u divide both sides by - 1)

so ... b=-5

I believe the answer is b = - 5