Ask Question
14 October, 00:51

Select from the drop-down menus to correctly complete the proof.

To prove that 2√⋅7 is irrational, assume the product is rational and set it equal to a/b, where b is not equal to 0. Isolating the radical gives 2√ = a/7b. The right side of the equation is (irrational, rational). Because the left side of the equation is (irrational, rational), this is a contradiction. Therefore, the assumption is wrong, and the product is (rational, irrational).

+1
Answers (1)
  1. 14 October, 01:33
    0
    We need to prove 2*√7 is an irrational number.

    Steps:

    1) To prove that 2√7 is an irrational, assume the product is rational and set it equal to a/b, where b is not equal to 0.

    2) Isolating the radical gives 2 = a/√7b.

    3) The right side of the equation is irrational.

    4) Because the left side of the equation is rational, this is a contradiction.

    5) Therefore, the assumption is wrong, and the product is irrational.
Know the Answer?