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11 November, 11:55

Give the general form of the equation of the line through (1,2) and is perpendicular to the line passing through (-6,-3) (6,3)

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  1. 11 November, 12:20
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    4x+3y-10=0

    Step-by-step explanation:

    first find the gradient of the line that is perpendicular to the line of interest.

    y2-y1/x2-x1

    3--3/6--6

    =3+3/6+6

    =9/12

    3/4

    The gradient of the line of interest is the negative reciprocal of 3/4. Therefore m is - 4/3

    next, substitute information into

    y-y1=m (x-x1)

    y-2=-4/3 (x-1)

    multiply both sides of equation by 3

    3y-6=-4 (x-1)

    expand brackets

    3y-6=-4x+4

    rearrange in general form

    4x+3y-10=0
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