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25 February, 15:15

So how would you break down the problem (2x-5) ^2=49

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Answers (2)
  1. 25 February, 15:31
    0
    To solve this you first expand the brackets.

    4x^2 - 20x + 25 = 49

    Then make it equal 0.

    4x^2 - 20x - 24 = 0

    Now solve the quardratic.

    x^2 - 5x - 6 = 0

    (x - 6) (x + 1) = 0

    x = 6 or x = - 1
  2. 25 February, 15:38
    0
    First, simplify the equation.

    4x2-20x+25 = 49

    Step 2: Subtract 49 from both sides.

    4x2-20x+25 = 49 - 49

    4x2-20x - 24 = 0

    Step 3: Factor left side of equation.

    4 (x+1) (x-6) = 0

    Step 4: Set factors equal to 0.

    x+1 = 0 or x - 6 = 0

    Your answers:

    x = - 1 or x = 6
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