With a short time remaining in the day a delivery driver has to make deliveries at 5 locations among the 6 locations remaining. How many different routes are possible

The delivery driver has to make deliveries at 5 locations among the 6 locations. This means the order of the probability is important because the route he will take from A to B is different with A to C.

So, you need to use permutation for this problem. The calculation would be:

6P5 = 6! / (6-5) ! = 720 different routes