Ask Question
10 November, 19:28

What is the 22nd term of the arithmetic sequence where a1 = 8 and a9 = 56?

+4
Answers (2)
  1. 10 November, 19:38
    0
    A 9 = a 1 + 8 d

    56 = 8 + 8 d

    8 d = 48

    as d is equal to 6

    so a22=a1+21d

    so we get by putting value 8+126

    which is 134
  2. 10 November, 19:39
    0
    A 1 = 8, a 9 = 56

    a 9 = a 1 + 8 d

    56 = 8 + 8 d

    8 d = 48

    d = 6 (common difference)

    a 22 = a 1 + 21 d = 8 + 21 · 6 = 8 + 126 = 134

    Answer: the 22nd term is 134.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the 22nd term of the arithmetic sequence where a1 = 8 and a9 = 56? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers