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5 May, 22:25

A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t^2 440t. after how many seconds does it reach its maximum height?

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  1. 5 May, 22:39
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    Velocity=-32t+440

    At maximum height, v=0

    0=-32t+440

    -440=-32t

    t=13.75 seconds
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