Ask Question
23 August, 05:44

Factor completely: 2x3 + 14x2 + 6x + 42

2[ (x2 + 3) (x + 7) ]

(2x2 + 6) (x + 7)

(x2 + 3) (2x + 14)

2 (x3 + 7x2 + 3x + 21)

+2
Answers (1)
  1. 23 August, 06:06
    0
    To factor all you do is ...

    Factor 2 x3 + 14 x2 + 6x + 42 2 x3 + 14 x2 + 6x + 42 = 2 (x+7) (x2 + 3) Answer: 2 (x+7) (x2 + 3)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Factor completely: 2x3 + 14x2 + 6x + 42 2[ (x2 + 3) (x + 7) ] (2x2 + 6) (x + 7) (x2 + 3) (2x + 14) 2 (x3 + 7x2 + 3x + 21) ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers