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18 April, 21:53

Which monomial is a perfect cube?

49p9q3r24

81p12q15r12

121p9q3r6

343p6q21r6

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  1. 18 April, 22:04
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    Ok, so dis is wat yo do

    xyz = (x) (y) (z)

    x^3y^3z^3 = (x^3) (y^3) (z^3)

    split it up, if one is not a perfect cube, it is wrong

    remember

    (x^n) ^m=x^ (mn)

    so

    (x^n) ^3 is a perfect cube (for nicety, make sure that n is a whole number)

    basically see which exponents are multiplules of 3

    first one

    49 is 7^2, not perfect cube

    wrong

    2nd one

    81=3^4, not a perfect cube

    wrong

    3rd one

    121=11^2,

    wrong, not perfect cube

    4th

    343=7^3

    p^6 = (p^2) ^3

    q^21 = (q^7) ^3

    r^6 = (r^2) ^3

    343p^6q^21r^6 = (7p^2q^7r^2) ^3

    answer is last one is perfect cube
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