If dy/dx = y cos x and y = 3 when x = 0, then y = ... ? Here are the answer choices

a) e^ (sinx) + 2

b) e^ (sinx) + 3

c) sin x + 3

d) sin x + 3e^x

e) 3e^ (sinx)

Question

28 February, 20:31

+1

Answers (1)

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Hailie · Answer 1

Dy/dx = y cos x

y = Ae^sin (x)

y (0) = Ae^sin (0) = A = 3

A = 3

Therefore, y = 3e^ (sinx)

If dy/dx = y cos x and y = 3 when x = 0, then y = ... ? Here are the answer choicesa) e^ (sinx) + 2b) e^ (sinx) + 3c) sin x + 3d) sin x + 3e^xe) 3e^ (sinx)