The equation of motion is given by s (t) = 6t2 + t + 8 at 1:05 P. M. What is the average velocity from 1:07 P. M. to 1:09 P. M. in meters/second?

The answer would be: 37m/s

Assuming that the unit t used is minutes after 1.:05,

when the time is 1:07 P. M. the value of t would be: 1:07 - 1:05 = 2

s (2) = 6 (2) ^2 + (2) + 8 = 34

when the time is 1:09 P. M. the value of t would be: 1:09 - 1:05 = 4

s (4) = 6 (4) ^2 + (4) + 8 = 108

Then, the function for average velocity would be:

average velocity = total distance/time

s (4) - s (2) / 4-2=

(108 - 34) / 2=

74/2 = 37m/s