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21 December, 16:35

An airplane flying into a headwind travels 1160 miles in 4 hours and 50 minutes. On the return flight, the distance is traveled in 4 hours. Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.

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  1. 21 December, 16:44
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    Let airspeed of the plane be x mph and wind speed = y mph. Then we have the following system of equations

    x - y = 1160 / 4.833 = 240.0166

    and

    x + y = 1160 / 4 = 290

    adding the 2 equations:-

    2x = 530.0166

    x = 265 mph = airspeed of the plane

    y = 290 - 265 = 25 mph = speed of the wind
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