Ask Question
17 October, 15:05

A Randstad/Harris interactive survey reported that 25% of employees said their company isloyal to them (USA Today, November 11, 2009). Suppose 10 employees are selected randomlyand will be interviewed about company loyalty.

Round your answers to four decimal places.

a. Is the selection of ten employees a binomial experiment?

Select: Yes/No

Explain.

The input in the box below will not be graded, but may be reviewed and considered by your instructor.

b. What is the probability that none of the 10 employees will say their company is loyal to them?

c. What is the probability that four of the 10 employees will say their company is loyal to them?

d. What is the probability that at least two of the 10 employees will say their company is loyal to them?

+5
Answers (1)
  1. 17 October, 15:08
    0
    a. yes

    b = 0.0563

    c. 0.1460

    d. 0.7560

    Step-by-step explanation:

    a. Yes. n = 10 identical trials with two possible outcomes on each with p = 0.25.

    b. p (x = 0) = 10! / (0!*10!) *.250*.7510 = 1 * 1 * 0.0563 = 0.0563.

    c. p (x = 4) = 10! / (4!*6!) *.254*.756 = 210 *.0039 * 0.1780 = 0.1460

    d. p (x = 1) = 10! / (1!*9!) *.251*.759 = 10 *.25 * 0.0751 = 0.1877

    p (x≥ 2) = 1 - p (x< 2) = 1 - (0.0563 + 0.1877) = 0.7560
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A Randstad/Harris interactive survey reported that 25% of employees said their company isloyal to them (USA Today, November 11, 2009). ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers