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13 January, 03:56

Costs for standard veterinary services at a local animal hospital follow a normal distribution with a mean of $88 and a standard deviation of $24. what is the probability that one bill for veterinary services costs between $42 and $133?

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  1. 13 January, 04:23
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    the probability that one bill for veterinary services costs between $42 and $133 will be given as follows

    P (42
    z = (x-μ) / σ

    where:

    μ-mean

    σ-standard deviation

    thus

    when x=42:

    z = (42-88) / 24=-1.92

    thus

    P (x<42) = 0.0281

    when x=133

    x = (133-88) / 24=1.875

    thus

    P (x<133) = 0.9699

    Thus

    P (42
    =0.9699-0.0281

    =0.9418

    Answer: 0.9418
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