The data in the table represent the training times (in minutes) for Adam. Adam 103 105 104 106 100 98 92 91 97 101 Find the five-number summary for the data. Min: Q_1: Q_2 (median) : Q_3: Max: Rubric:

Given dа ta:

103, 105, 104, 106, 100, 98, 92, 91, 97, 101

First, we have to rearrange it from least to the greatest.

91, 92, 97, 98, 100, 101, 103, 104, 105, 106

The maximum value is 106 and the least value is 91.

Therefore the range is = 106 - 91

Range = 15

Now,

The median is the middle value, which is = (100 + 101) : 2

median = 100.5 minutes → (Q2)

Now,

The first or lower quartile (Q1) is the median of the least value and the Q2.

Q1 = (100.5 + 91) : 2

Q1 = 95.75 minutes.

Lastly, the upper quartile or the third quartile is the median of Q2 and the maximum value.

Q3 = (100.5 + 106) : 2

Q3 = 103.25 minutes

Thus,

Interquartile range = Q3 - Q1

Interquartile range = 103.25 - 97.75

Interquartile range = 5.5 minutes.