Ask Question
28 August, 08:56

Elija got a job as an office clerk in 2000. At the end of every year, Elija has gotten either a raise, a promotion, or both. Elija's salary, S (t), can be determined by multiplying his starting annual salary, $24,400, by the natural logarithm of the product of 3.3 and the number of years since 2000, t. Which of the following correctly models the situation and gives the average rate of change of Elija's salary between 2002 and 2005?

+4
Answers (1)
  1. 28 August, 09:13
    0
    Elija's salary: S (t) = $24,400 ln (3.3t)

    Number of years since 2000: t

    Average rate of change of Elija's salary between 2002 and 2005: r=?

    Year 2002→t=2002-2000→t=2 years

    Year 2005→t=2005-2000→t=5 years

    r=[S (b) - S (a) ] / (b-a); a=2, b=5

    r=[S (5) - S (2) ] / (5 years-2 years)

    r=[S (5) - S (2) ] / (3 years)

    t=5→S (5) = $24,400 ln [3.3 (5) ]

    S (5) = $24,400 ln (16.5)

    t=2→S (2) = $24,400 ln [3.3 (2) ]

    S (2) = $24,400 ln (6.6)

    r=[S (5) - S (2) ] / (3 years)

    r=[$24,400 ln (16.5) - $24,400 ln (6.6) ] / (3 years)

    Common factor $24,400

    r=$24,400 [ln (16.5) - ln (6.6) ] / (3 years)

    r=$24,400 ln (16.5/6.6) / (3 years)

    r=$24,400 ln (2.5) / (3 years)

    r=$24,400 ln (2.5) / (3 years)

    r=$24,400 (0.916290732) / (3 years)

    r=$22,357.49385 / (3 years)

    r=$7,452.497952/year

    r=$7,452.50/year

    The average rate of change of Elija's salary between 2002 and 2005 is $24,400 ln (2.5) / (3 years) or $7,452.50/year
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Elija got a job as an office clerk in 2000. At the end of every year, Elija has gotten either a raise, a promotion, or both. Elija's ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers