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15 March, 19:12

What is the center of the circle given by the equation (x-6) 2 + (y+3) 2=72? A. (-6, 3) B. (-3, 6) C. (6, - 3) D. (6, 7)

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  1. 15 March, 19:32
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    The center of the circle is the x and y in the equation.

    To find the center you need to solve for x and Y when the equations inside parenthesis are set to zero.

    (x-6) = 0

    x = 6

    (y+3) = 0

    y = - 3

    The center of the circle is (6,-3)
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