Randy divides (2x4 - 3x3 - 3x2 + 7x - 3) by (x2 - 2x + 1) as shown below. What error does Randy make?

To divide (2x^4 - 3x^3 - 3x^2 + 7x - 3) by (x^2 - 2x + 1). First, divide 2x^4 by x^2 to get 2x^2, then multiply (x^2 - 2x + 1) by 2x^2 to get 2x^4 - 4x^3 + 2x^2 and subtract 2x^4 - 4x^3 + 2x^2 from 2x^4 - 3x^3 - 3x^2 + 7x - 3 to get x^3 - 5x^2 + 7x - 3. Next, divide x^3 by x^2 to get x, then multiply (x^2 - 2x + 1) by x to get x^3 - 2x^2 + x and subtract x^3 - 2x^2 + x from x^3 - 5x^2 + 7x - 3 to get - 3x^2 + 6x - 3. Next, divide - 3x^2 by x^2 to get - 3, then mulntiply (x^2 - 2x + 1) by - 3 to get - 3x^2 + 6x - 3 and subtract - 3x^2 + 6x - 3 from - 3x^2 + 6x - 3 to get 0. Therefore, (2x^4 - 3x^3 - 3x^2 + 7x - 3) divided by (x^2 - 2x + 1) = 2x^2 + x - 3

Randy makes an error in quoting the x-term, the answer is C