Suppose that the length of a certain rectangle is 8 meters less than four times its width. the perimeter of the rectangle is 54 meters. find the length and width of the rectangle.

Length = 4w-8

P = 2L + 2W

54 = 2 (4w-8) + 2W

54 = 8w - 16 + 2W

54 = 10w - 16

54+16 = 10w - 16+16

70=10w

70/10=10w/10

w=7

L = 4 (7) - 8

L = 28-8

L = 20

Check

P = 2w + 2L

54 = 2 (7) + 2 (20)

54 = 14 + 40

54=54