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30 January, 05:07

Verify (a+b+c) ^2=a^2+b^2+c^2+2ab+2bc+2ca

With the observation answer

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  1. 30 January, 05:15
    0
    see explanation

    Step-by-step explanation:

    (a + b + c) ² = (a + b + c) (a + b + c)

    Each term in the second factor is multiplied by each term in the firs factor, that is

    a (a + b + c) + b (a + b + c) + c (a + b + c) ← distribute all 3 parenthesis

    = a² + ab + ac + ab + b² + bc + ac + bc + c² ← collect like terms

    = a² + b² + c² + 2ab + 2bc + 2ac
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