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17 October, 18:13

To determine a 72 percent level of confidence for a proportion, the value of z is approximately:

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  1. 17 October, 18:28
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    To solve this problem, we have to make use of the standard probability distribution tables for z test.

    Since we are asked to find for the 72 percent level confidence, then this means we are to look for the value of z which gives (100-72) / 2 = 14% on both sides of the tail.

    So at 14% tail on one side, the z value is approximately:

    1.08

    Answer:

    ± 1.08
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